tìm x biết \(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}+\frac{x}{78}=\frac{220}{39}\)
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}+\frac{x}{78}=\frac{220}{39}\)
\(\Leftrightarrow x\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}+\frac{1}{66}+\frac{1}{78}+\frac{1}{78}\right)=\frac{220}{39}\)
\(\Leftrightarrow x\cdot\frac{20}{39}=\frac{220}{39}\Rightarrow x=11\)
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}+\frac{x}{78}=\frac{220}{39}\)
\(=>x=\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}+\frac{1}{66}+\frac{1}{78}+\frac{1}{78}=\frac{220}{39}\)
\(x\cdot\frac{20}{39}=\frac{220}{39}\)
\(x=\frac{220}{39}:\frac{20}{39}=11\)
Câu 1 tính hợp lí
a,A=\(\frac{-9}{11}.\frac{3}{8}-\frac{9}{11}.\frac{5}{8}+\frac{17}{11}\)
b,B=\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{53.55}\)
Câu2 tìm x
a,\(x+5-\frac{1}{2}=3\frac{1}{2}\)
b,\(3^{x+1}=27\)
c,\(2016.\left[25-\left(3x+2\right)\right]=3^2.7\)
d,\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{60}+\frac{x}{78}=\frac{220}{39}\)
Ai giải nhanh tớ tick cho
Thank you
\(-\frac{9}{11}\cdot\frac{3}{8}-\frac{9}{11}\cdot\frac{5}{8}+\frac{17}{11}=-\frac{9}{11}\left(\frac{3}{8}+\frac{5}{8}\right)+\frac{17}{11}=-\frac{9}{11}\cdot1+\frac{17}{11}=1\)
\(\frac{2}{1.3}+....+\frac{2}{53.55}=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{53}-\frac{1}{55}=1-\frac{1}{55}=\frac{54}{55}\)
\(x+5-\frac{1}{2}=3\frac{1}{2}\)
\(x+5=3.5+0.5=4\)
\(x=4-5=-1\)
\(3^{x+1}=27=3^3\)
\(x+1=3\)
vậy x=2
bây h bn mún tớ iair hộ bn trừ câu cuối ko
\(2016\left\{25-\left(3x+2\right)\right\}=63\)
\(3x+2=24.96875\)
tự tính
Bài 1:Một xe tải chạy từ A và có thể đến B sau 6 giờ .Sau khi xe tải chạy được 2 giờ thì 1 xe ô tô con khởi hành từ B chạy về A và gặp xe tải sau 1 giờ 36 phút .tính thời gian xe con chạy từ B về A
Bài 2:Tìm x biết
a,\(\frac{x}{6}\)\(+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}=\frac{220}{39}\)
b,\(2+4+6+....+2x=156\)
Bài 3:So sánh
a,A=\(\frac{2015}{x^m}+\frac{2015}{x^n}\)Và B=\(\frac{2014}{x^m}+\frac{2016}{x^n}\)
b,C=\(\frac{2015\cdot2016-1}{2015\cdot2016}\)Và D=\(\frac{2016\cdot2017-1}{2016\cdot2017}\)
c,E=\(\frac{5}{10^{2015}}+\frac{11}{10^{2016}}\)Và F=\(\frac{11}{10^{2015}}+\frac{5}{10^{2016}}\)
d,S=\(\frac{1}{2}+\frac{2}{2^3}+.....+\frac{n}{2^n}+.....+\frac{2017}{2^{2017}}\) \(với\)\(2\)
1. Tính giá trị
a,\(D=\left[\frac{1}{2^2}-1\right]\left[\frac{1}{3^2}-1\right]\left[\frac{1}{4^2}-1\right]...\left[\frac{1}{100^2}-1\right]\)
b, Tìm \(x\inℤ\)biết :
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}+\frac{x}{45}+\frac{x}{55}+\frac{x}{66}+\frac{x}{78}=\frac{220}{39}\)
c, Cho \(A=\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2010}\)
\(B=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{17}\)
So sánh A và B
2.a,Cho M là trung điểm của đoạn thẳng AB.Trên tia đối của tia BA lấy điểm I sao cho \(IM=a(a>0)\)
Tính IA + IB theo a
b, Trên đường thẳng xy lấy điểm A vẽ hai tia Az và At,trên 2 nửa mặt phẳng đối nhau có bờ là xy sao cho góc \(\widehat{yAz}=\frac{1}{2}\widehat{yAt}\). Tìm số đo góc \(\widehat{yAz}\)để góc \(\widehat{xAz}=3\widehat{xAt}\)
\(D=\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{9999}{100^2}\)
\(=\frac{1.3}{2^2}.\frac{2.4}{3^2}.\frac{3.5}{4^2}...\frac{99.101}{100^2}\)
\(=\frac{1.2...99}{2.3...100}.\frac{3.4....101}{2.3....100}=\frac{1}{100}.\frac{101}{2}=\frac{101}{200}\)
1 b) Đặt A=\(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{66}+\frac{1}{78}\)
=> \(\frac{A}{2}=\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{132}+\frac{1}{156}=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{11.12}+\frac{1}{12.13}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}=\frac{1}{3}-\frac{1}{13}\)
=> \(A=\frac{2}{3}-\frac{2}{13}\)\(=\frac{20}{39}\)
Ta có: \(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+...+\frac{x}{78}=\frac{220}{39}\)
<=> \(x\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{15}+...+\frac{1}{78}\right)=\frac{220}{39}\Leftrightarrow x.\frac{20}{39}=\frac{220}{39}\Leftrightarrow x=11\)
\(B=\left(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\right)+\left(\frac{1}{6}+\frac{1}{7}+\frac{1}{8}\right)+\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{11}\right)+\left(\frac{1}{12}+\frac{1}{13}+\frac{1}{14}\right)+\left(\frac{1}{15}+\frac{1}{16}+\frac{1}{17}\right)\)
\(< \left(\frac{1}{3}+\frac{1}{3}+\frac{1}{3}\right)+\left(\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\right)+\left(\frac{1}{9}+\frac{1}{9}+\frac{1}{9}\right)+\left(\frac{1}{12}+\frac{1}{12}+\frac{1}{12}\right)+\left(\frac{1}{15}+\frac{1}{15}+\frac{1}{15}\right)\)\(=3.\frac{1}{3}+3.\frac{1}{6}+3.\frac{1}{9}+3..\frac{1}{12}+3.\frac{1}{15}=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}< 1+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=3\)
=> B<3
\(A=\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2010}=1-\frac{1}{2011}+1-\frac{1}{2012}+1+\frac{2}{2010}=3-\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2010}+\frac{1}{2010}\)
\(>3-\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2012}=3\)
=> A>3
Vậy A>3>B
Có thể chứng minh :
A>2,5>B
... nhiều cách khác nữa
Tìm x, biết:
\(x=\left(2-\frac{5}{3}+\frac{7}{6}-\frac{9}{10}+\frac{11}{15}-\frac{13}{21}+\frac{15}{28}-\frac{17}{36}+\frac{19}{45}\right)\times\frac{5}{3}\)
tìm x biết
\(\frac{x}{6}\)+ \(\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}.\)
\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)=\frac{8}{9}\)
\(\Rightarrow x.\frac{23}{52}=\frac{8}{9}\)
\(\Rightarrow x=\frac{426}{207}\)
Study well
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)
<=> x\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{x}{39}\right)=\frac{8}{9}\)
<=> x = \(\frac{8}{9}:\frac{23}{52}\)
<=> x = \(\frac{416}{207}\)
Tứ chép đề bài :vv
\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)x=\frac{8}{9}\)
\(\frac{23}{52}x=\frac{8}{9}\)
\(x=\frac{8}{9}:\frac{23}{52}\)
\(x=\frac{416}{207}\)
Vậy .....
Cho đa thức : f(x)=x(x^19-x^5-x^2018) và g(x)= x^2019-x^2020+9+(x^4+x^2+2)
1)Tính k(x)=f(x)+g(x)
2)Tính giá trị của k(x) tại x bằng \(\left(2-\frac{5}{3}+\frac{7}{6}-\frac{9}{10}+\frac{11}{15}-\frac{13}{21}+\frac{15}{28}-\frac{17}{36}+\frac{19}{45}\right)\cdot\frac{5}{6}\)
3) CMR k(x) không nhận giá trị 2019 với mọi giá trị nguyên x
Tìm số tự nhiên x, biết:
a, \(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-....-\frac{20}{53-55}=\frac{3}{11}\)
b, \(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=\frac{-37}{45}\)
c,\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)
Giải phương trình sau:
1) \(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+6}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\)
2) \(\frac{x-241}{17}+\frac{x-220}{19}+\frac{x-195}{21}+\frac{x-166}{23}=0\)
3) \(\frac{x+2}{13}+\frac{2x-45}{15}=\frac{3x+8}{37}+\frac{4x+69}{9}\)
\(\Leftrightarrow\left(\frac{x+14}{86}+1\right)+\left(\frac{x+15}{85}+1\right)+\left(\frac{x+16}{84}+1\right)+\left(\frac{x+17}{83}+1\right)+\left(\frac{166}{4}-4\right)=0\)
\(\Leftrightarrow\frac{x+100}{86}+\frac{x+100}{85}+\frac{x+100}{84}+\frac{x+100}{83}+\frac{x+100}{4}=0\)
\(\Leftrightarrow\left(x+100\right).\left(\frac{1}{86}+\frac{1}{85}+\frac{1}{84}+\frac{1}{83}+\frac{1}{4}\right)=0\)
\(\Leftrightarrow\left(x+100\right)=0\Rightarrow x=-100\left(\text{vì }\frac{1}{86}+\frac{1}{85}+\frac{1}{84}+\frac{1}{83}+\frac{1}{4}\right)\ne0\)
